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| sapan.gcet |
 Posted: Tue Oct 27, 2009 6:42 am |
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Joined: 29 Sep 2009
Posts: 10
Location: Mumbai
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Hi,
Lets assume that we have a list where,
List -> integer | List;
eg L1 = [1,[[2,3]],[4]].
when I perform
binary_to_list(list_to_binary(L1))
The result is [1,2,3,4]. I loose the original structure of the list.
How do then the serialization of the list is done?
Is there any other way we can perform 'binary_to_list(list_to_binary(L))'
functionality maintaining the structure of the list??
--
Regards,
Sapan Shah
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| maxlapshin |
| Posted: Tue Oct 27, 2009 6:45 am |
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Joined: 15 Sep 2009
Posts: 159
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term_to_binary, binary_to_term
________________________________________________________________
erlang-questions mailing list. See http://www.erlang.org/faq.html
erlang-questions (at) erlang.org
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| sapan.gcet |
| Posted: Tue Oct 27, 2009 6:50 am |
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Joined: 29 Sep 2009
Posts: 10
Location: Mumbai
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Thanks... missed this part...
On Tue, Oct 27, 2009 at 12:13 PM, Max Lapshin <max.lapshin@gmail.com> wrote:
> term_to_binary, binary_to_term
>
--
Regards,
Sapan Shah
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| Guest |
| Posted: Wed Oct 28, 2009 12:11 am |
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Guest
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On Oct 27, 2009, at 7:40 PM, sapan shah wrote:
> eg L1 = [1,[[2,3]],[4]].
> when I perform
> binary_to_list(list_to_binary(L1))
> The result is [1,2,3,4]. I loose the original structure of the list.
That's because list_to_binary/1 is defined to take an "iolist",
which is a tree structure whose leaves are binaries and *bytes*,
flatten it, and give you a binary. Had you tried a larger integer,
such as list_to_binary([999]), you would have had even more trouble.
What you want is term_to_binary/1 to do the encoding
and binary_to_term/1 to do the decoding.
Searching the 'erlang' manual page for 'to_binary' and 'binary_to'
would have found these.
________________________________________________________________
erlang-questions mailing list. See http://www.erlang.org/faq.html
erlang-questions (at) erlang.org
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| wuji |
| Posted: Wed Aug 22, 2012 6:27 am |
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Joined: 10 Aug 2012
Posts: 654
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